Answer:
g( f(2)+3) = 30
Explanation:
step(i):-
Given function g(t)=t²-t and f(x)=1+x
given f(x)=1+x
f(2) = 1 + 2 =3
step(ii):-
g( f(2)+3) = g(3 + 3)
= g(6)
= (6)² - 6
= 36 -6
= 30
Conclusion:-
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