Answer:
One end of the ladder rests at 8 feet on the wall.
Explanation:
In the figure attached,
AC is a ladder 10 feet long leaning against the wall.
Distance of it's one end from the wall = 6 feet
Let the ladder rests on the wall at the height = h feet
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
(10)² = h² + 6²
h² = 100 - 36
h = √64
h = 8 feet
Therefore, one end of the ladder rests at 8 feet on the wall.