Question

Given that f(x)=x^2+4x-32f(x)=x

2 +4x−32 and g(x)=x-4g(x)=x−4, find (f+g)(x)(f+g)(x) and express the result in standard form.

Answer 1

To find (f+g)(x), simply add f(x) =
`x^2` + 4x - 32 and g(x) = x - 4 together to get (f+g)(x) =
`x^2` + 5x - 36, which is in standard form.

Step-by-step explanation:

To find (f+g)(x), you need to add the functions f(x) and g(x) together. The function f(x) is given as f(x) =
`x^2` + 4x - 32 and g(x) as g(x) = x - 4. We add the two functions by combining like terms.

f(x) =
`x^2` + 4x - 32

g(x) = x - 4

The sum of these functions is:

(f+g)(x) = (
`x^2` + 4x - 32) + (x - 4)

We combine like terms to get:

(f+g)(x) =
`x^2` + 5x - 36

This is the sum of functions f(x) and g(x) in standard form.

Answer 2

So your question was not very clear but with (f+g) im guessing thats f(x)+g(x)

So first we add them x^2+4x-32 + x-4 then we will get x^2 + 5x - 36

Then we need to multiply both

(x^2+5x-36)(x^2+5x-36)

=

(x^2+5x-36)^2

The only reason im not solving it out is because it yields large numbers and you might not understand.