Question

Using the following data on the Observations 10, 13, 4, and 20 confirm that the complete linkage distance between the cluster containing 《10, 13) and the cluster containing (4, 20) s 2.577 units as displayed in the dendrogram

Observation
13 20 0.032 0.195 -0510 0.466 0.741 0.8750.207 0.474 0.700 0.748 -0.004 -0.490 -0.892 0.735 0.219 0.655 -0.1731.013 0.943 0.083 -0.693 -0.489-0.702 -0.458 1.620 2.275 1328 1.733 -0.863 1.035 0.724 0.721 10 Income/Debt Return Cost Load Peak Sales TotalFuelCosts
If required, round your answers to three decimal places.Do not round intermediate calculations
1. Distance from Observation 10 and Observation 4:
2. Distance from Observation 10 and Observation 20:
3. Distance from Observation 13 and Observation 4:
4. Distance from Observation 13 and Observation 20:

Answer 1

Explanation:

The distance between:

10 and 4: 1.492

10 and 20: 2.055

13 and 4: 2.577

13 and 20: 2.226

The R code:

#Convert your datafile into csv and make sure your row names are 10,13,4 and 20

data=read.csv(file.choose())

data

row.names(data)=c(10,13,4,20)

data

d=dist(data,method="euclidean")

d

fit=hclust(d,method="complete")

plot(fit)

groups=cutree(fit,k=2)

rect.hclust(fit,k=2,border="red")