Question

There are __________ moles of N atoms present in a 2.0 g C8H10O2N4.

Answer 1

`n_N=0.041molN`

Step-by-step explanation:

Hello,

In this case, for this mole-mass relationship, we are able to compute the moles of nitrogen atoms by firstly obtaining the moles of the given compound, considering its molar mass that is 194 g/mol:

`n_{C_8H_(10)O_2N_4}=2.0gC_8H_(10)O_2N_4*(1molC_8H_(10)O_2N_4)/(194gC_8H_(10)O_2N_4) =0.01molC_8H_(10)O_2N_4`

Then, by knowing that one mole of the given compound has four moles of nitrogen atoms, we apply the following relationship:

`n_N=0.01molC_8H_(10)O_2N_4*(4molN)/(1molC_8H_(10)O_2N_4) \\\\n_N=0.041molN`

Best regards.