Question

PLEASE HELP ME I GIVE BRANLYIEST

A school surveyed students, asking whether they are right-handed or left-handed. This table provides data from the survey.


Right-Handed Left-Handed

Boys 108 23

Girls 99 16


Fill the tables with the relative frequencies. If necessary, round your answers to the nearest hundredth.

Answer 1

first box= boys= .82, .18 girls= .86, 14

second box= boys= .52 .59 girls= .48 .41

Explanation:

i did the test

Answer 2

`\left\begin{array}{ccc}&Right-Handed&Left-Handed\\Boys&108&23\\Girls&99&16\end{array}\right`

`.18+.82=1`

`.14+.86=1`

`\left[\begin{array}{cccc}&Right-Handed&Left-Handed&Total\\Boys&.82&.18&1\\Girls&.86&.14&1\end{array}\right]`

`.41+.59=1`

`.48+.52=1`

`\left[\begin{array}{ccc} &Right-Handed&Left-Handed\\Boys&.52&.59\\Girls&.48&.41\\Total&1&1\end{array}\right]`

Step by Step:

Step which two decimals added together equal 1?

0.86, 0.48, 0.41, 0.82, 0.59, 0.14, 0.52, 0.18

`0.14+0.86=1`,
`0.18+0.82=1`,
`0.41+0.59=1`, &
`0.48+0.56=1`

Now solve for the rows in the first table

`108+23=131\\108 divided by 131=0.82\\Well remember,0.82+0.18=1`

so there is the first row for boys in the first table

Now solve for the second rows in the first table

`99+16=115\\99 divided by 115=0.86\\Well remember, 0.86+0.14=1`

so there is the second row for girls in the first table

Now we do pretty much the same for table 2 just it's columns instead of rows

`108+99=207\\108 divided by 207=0.52\\Well remember 0.52+0.48=1`

So we put 0.52 under boys RH(right-handed) and 0.48 under girls RH.

`23+16=39\\23 divided by 39=0.59\\Well remember, 0.59+0.41=1`

So we put 0.59 under boys LH(left-handed) and 0.41 under girls LH.

Hope this makes sense and helps!!!