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What is 9y5−4y3−8y7−5y6+3y4 written in standard form?

User Duwalanise
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1 Answer

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Answer:

-8y^7 - 5y^6 + 9y^5 + 3y^4 - 4y^3

Explanation:

Please be sure to use " ^ " to indicate exponentiation. Then,

your 9y5−4y3−8y7−5y6+3y4 becomes 9y^5 - 4y^3 - 8y^7 - 5y^6 + 3y^4.

We must now write that in descending order by powers of y:

-8y^7 - 5y^6 + 9y^5 + 3y^4 - 4y^3

User TzurEl
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