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Factor 12q^2+34q-28. Include list of factors.

1 Answer

1 vote

Answer:

2(2q+7)(3q-2)=0

Explanation:

lets set up the equation equal to 0:

12q^2+34q-28=0

now, lets factor:

2(6q^2+17q-14)=0

2(2q+7)(3q-2)=0

now, lets find the solutions:

2q+7=0

2q=-7

q=-3.5

3q-2=0

3q=2

q=2/3

User Rocky Zhang
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