Final answer:
When 3-chloro-3-methylpentane reacts with sodium tert-butoxide in tert-butanol, an elimination reaction occurs, resulting in the formation of 3-methyl-3-pentene as the major product.
Step-by-step explanation:
When 3-chloro-3-methylpentane reacts with sodium tert-butoxide in tert-butanol, an elimination reaction occurs. The reaction mechanism is known as E2 (bimolecular elimination).
The elimination reaction involves the loss of a hydrogen atom and a leaving group (chlorine in this case) from adjacent carbon atoms, resulting in the formation of a double bond in the product compound. In this case, the major product formed will be 3-methyl-3-pentene.
It is important to consider the stereochemistry of the reaction. Since the reaction does not involve any chiral centers, the stereochemistry of the reactant does not affect the stereochemistry of the product.