Question

Which is the equation in point slope form for the line that passes through (3,7) and is perpendicular to 3x-5y=8?

Answer 1

Explanation:

eq. of line is 3x-5y=8

5y=3x-8

y=3/5 x-8/5

its slope=3/5

slope of line perpendicular to it=-5/3

eq of line with slope -5/3 and passing through (3,7) is

y-7=-5/3(x-3)

or 3y-21=-5x+15

or 5x+3y=15+21

or 5x+3y=36