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Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.8 x 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven-the driving force is transferred to the object, which oscillates instead of the entire building X 50%

Part (a) What effective force constant, in N/m, should the springs have to make them oscillate with a period of 1.2 s? k = 9.5 * 106 9500000 X Attempts Remain 50%
Part (b) What energy, in joules, is stored in the springs for a 1.6 m displacement from equilibrium?

User Nyan
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1 Answer

5 votes

Answer:

The force constant is
k =1.316 *10^(7) \ N/m

The energy stored in the spring is
E = 1.68 *10^(7) \ J

Step-by-step explanation:

From the question we are told that

The mass of the object is
M = 4.8*10^(5) \ kg

The period is
T = 1.2 \ s

The period of the spring oscillation is mathematically represented as


T =2 \pi \sqrt{ (M)/(k)}

where k is the force constant

So making k the subject


k = (4 \pi ^2 M )/(T^2)

substituting values


k = (4 (3.142) ^2 (4.8 *10^(5)) )/((1.2)^2)


k =1.316 *10^(7) \ N/m

The energy stored in the spring is mathematically represented as


E = (1)/(2) k x^2

Where x is the spring displacement which is given as


x = 1.6 \ m

substituting values


E = (1)/(2) (1.316 *10^(7)) (1.6)^2


E = 1.68 *10^(7) \ J

User Fromthestone
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7.7k points