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41 votes
41 votes
4. The work output is 500 joules for a machine that is 12.5 percent efficient. The work input is

joules. 0
(1 Point)
A.4000
B.1.000
C.2,000
D.12.500

4. The work output is 500 joules for a machine that is 12.5 percent efficient. The-example-1
User Tije
by
3.0k points

1 Answer

12 votes
12 votes

Answer:

4000 J

Step-by-step explanation:

x * .125 = 500

x = work input = 500 / .125 = 4000 J

User Towr
by
3.2k points