Register
What is the solution set for the equation (x-2)(x-8)=0
191k views
4 votes
What is the solution set for the equation (x-2)(x-8)=0

User Jlaur
by
4.5k points

2 Answers

5 votes

Answer:x = 2 and x = 8

Explanation:

( 2 - 2)( 8 - 8)

(0)(0)

=0

User Volshebnik
by
4.4k points
6 votes

Answer:

x=2 x =8

Explanation:

(x-2)(x-8)=0

Using the zero product property

x-2 = 0 x-8 = 0

x=2 x =8

User Cliff Viegas
by
4.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.6m questions

5.9m answers

Other Questions

Help easy for you but not for me!
How many downloads did song 1 have at minute 3?
The Pythagorean Theorem is an equation that helps you to find the lengths of a right triangle. The legs are given as a and b while the hypotenuse is labeled in the theorem's formula: a2+b2=c2 If you know
In the triangles, HG = MP and GK = PN. Which statement about the sides and angles is true?
7 more than a number is the same as 2 times the number minus 11
Link Copied!