Question

When 10b=5 is solved for c, one equation is c=(2b-2)^2

Answer 1

b= 1/2

c = 1

Explanation:

10b = 5

You want to leave the variable b on it's own so you divide both sides by 10

10b/10 = 5/10 --> b = 5/10 or 1/2

Since you have the value of b now, plug it in to solve for the value of c

c = (2 (1/2) - 2)^2

= (1 - 2)^2 Half of 2 is 1, of course

= (-1)^2 (-1 * -1)

c = 1 (a negative times a negative is a positive

So the value of be is 1/2 and c is 1

Hope this helps!