Question

What force is exerted on a test charge of 3.25 E−5 C, if it is placed in an electric field of magnitude 1.40 E4 N/C? Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.

Answer 1

your answer is 1.50 E4 N/C

Explanation:

Answer 2

0.46 newtons

Explanation:

For these kinds of problems, you can employ the formula

`E=(F)/(q)`

where E represents the field in N/C, F represents the force in newtons, and q represents the charge in coulombs. You can therefore set up the following equation:

`1.4* 10^4 N/C=(F)/(3.25* 10^(-5)C) \\\\`

`F=(1.4* 10^4 N/C) * (3.25 * 10^(-5) C)=4.6 * 10^(-1) N` (following sig figs)

Hope this helps!