147k views
4 votes
What are the coordinates of the center of a circle whose equation is (x+1)^2+y^2=100?

User Flavius
by
7.4k points

2 Answers

1 vote

Answer:

radius = 10

center = (- 1, 0)

Explanation:

eqn. of the circle = (x - h)^2 + (y - k)^2 = r^2

= (x + 1)^2 + y^2 = 100

(x - (-1))^2 + (y - 0)^2 =10^2

The center is (- 1, 0) and the radius is 10

Hope this helps!

User Jonesopolis
by
7.3k points
4 votes

Answer:

The center is (-1,0) and the radius is 10

Explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where the center is (h,k) and the radius is r

(x+1)^2+y^2=100

(x - -1)^2+(y-0)^2=10^2

The center is (-1,0) and the radius is 10

User GoldenAge
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories