Question

What are the coordinates of the center of a circle whose equation is (x+1)^2+y^2=100?

Answer 1

radius = 10

center = (- 1, 0)

Explanation:

eqn. of the circle = (x - h)^2 + (y - k)^2 = r^2

= (x + 1)^2 + y^2 = 100

(x - (-1))^2 + (y - 0)^2 =10^2

The center is (- 1, 0) and the radius is 10

Hope this helps!

Answer 2

The center is (-1,0) and the radius is 10

Explanation:

We can write the equation of a circle as

(x-h)^2 + (y-k)^2 = r^2

where the center is (h,k) and the radius is r

(x+1)^2+y^2=100

(x - -1)^2+(y-0)^2=10^2

The center is (-1,0) and the radius is 10