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Probability question, which I am stuck on!

The probabilities of landing on 1, on 2, on 4, on 5 or on 6 when rolling a biased dice are shown in the table.
*Table In Attachment*

The biased dice is rolled 300 times.
Estimate the total number of times the dice will land on 3 or on 4.

I would like to know what a biased dice is too!

Probability question, which I am stuck on! The probabilities of landing on 1, on 2, on-example-1

2 Answers

6 votes

Answer:

99

Explanation:

3=0.12

3 =0.12×300=36

4 =0.21×300=63

63+36= 99

User Bart Ten Brinke
by
5.5k points
1 vote

Answer:

land on 3: 36 times

land on 4: 63 times

Explanation:

A biased dice is the opposite of a fair dice.

A fair dice has the same probability of landing any of the six numbers: 1/6

The biased dice has different probabilities for its results.

To solve this question, first we need to find the probability of landing a 3.

The sum of all probabilities need to be 1, so:

0.13 + 0.05 + p(3) + 0.21 + 0.19 + 0.3 = 1

p(3) = 1 - 0.88 = 0.12

If we roll the dice 300 times, the expected number of times the dice will land:

on 3: 300 * p(3) = 300 * 0.12 = 36 times

on 4: 300 * p(4) = 300 * 0.21 = 63 times

User VoteCoffee
by
5.2k points