Answer:
12,13,14,15,16
Explanation:
\underline{\text{Define Variables:}}
Define Variables:
May choose any letters.
\text{Let }t=
Let t=
\,\,\text{the number of tables sold}
the number of tables sold
\text{Let }c=
Let c=
\,\,\text{the number of chairs sold}
the number of chairs sold
\text{\textquotedblleft at most 25 pieces"}\rightarrow \text{25 or fewer pieces}
“at most 25 pieces"→25 or fewer pieces
Use a \le≤ symbol
Therefore the total number of furniture pieces sold, t+ct+c, must be less than or equal to 25:25:
t+c\le 25
t+c≤25
\text{\textquotedblleft no less than \$7000"}\rightarrow \text{\$7000 or more}
“no less than $7000"→$7000 or more
Use a \ge≥ symbol
The store makes $550 for each table sold, so for tt tables, the store will make 550t550t dollars. The store makes $100 for each chair sold, so for cc chairs, the store will make 100c100c dollars. Therefore, the total revenue 550t+100c550t+100c must be greater than or equal to \$7000:$7000:
550t+100c\ge 7000
550t+100c≥7000
\text{Plug in }9\text{ for }c\text{ and solve each inequality:}
Plug in 9 for c and solve each inequality:
The store sold 9 chairs
\begin{aligned}t+c\le 25\hspace{10px}\text{and}\hspace{10px}&550t+100c\ge 7000 \\ t+\color{green}{9}\le 25\hspace{10px}\text{and}\hspace{10px}&550t+100\left(\color{green}{9}\right)\ge 7000 \\ t\le 16\hspace{10px}\text{and}\hspace{10px}&550t+900\ge 7000 \\ \hspace{10px}&550t\ge 6100 \\ \hspace{10px}&t\ge 11.09 \\ \end{aligned}
t+c≤25and
t+9≤25and
t≤16and
550t+100c≥7000
550t+100(9)≥7000
550t+900≥7000
550t≥6100
t≥11.09
\text{The values of }t\text{ that make BOTH inequalities true are:}
The values of t that make BOTH inequalities true are:
\{12,\ 13,\ 14,\ 15,\ 16\}
{12, 13, 14, 15, 16}
\text{(the final answer is this entire list)}
(the final answer is this entire list)