Question

A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of 1.12 T between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at 0.280 T/s.

A. What is the magnitude of the electric field induced in the ring?
B. In which direction (clockwise or counterclockwise) does the current flow as viewed by someone on the south pole of the magnet?1. Counterclockwise2. Clockwise

Answer 1

According to Faraday's law of electromagnetic induction, the magnitude of the electric field induced in the ring is 22.9 V/m, and the current flows clockwise as viewed from the south pole of the magnet.

Step-by-step explanation:

The magnitude of the electric field induced in the ring can be found using Faraday's law of electromagnetic induction.

The formula for calculating the magnitude of the induced electric field is given by:

E = -d(BA)/dt

Where E is the magnitude of the induced electric field, B is the magnetic field, A is the area of the ring, and dt is the change in time.

Substituting the given values, we have:

E = -d(1.12T * π * (4.60cm/2)²) / dt = -d(1.12T * π * 5.90cm²) / dt = -(1.12T * π * 5.90cmMARUTI 10900 CEMARUTI 10900 CE) / (0.280s)

Simplifying the equation, we find that the magnitude of the electric field induced in the ring is approximately 22.9 V/m.

The direction of the induced current can be determined by using the right-hand rule. Since the magnetic field is decreasing, the induced current will flow in the clockwise direction as viewed by someone on the south pole of the magnet.