Answer:
Solution set: (3, 4) and (4, 3)
Explanation:
Please, to indicate exponentiation, use " ^ ": a^2 and b^2
Then you have:
a + b = 7 and a^2 + b^2 = 25.
Let's eliminate b: Solve a + b = 7 for b, obtaining b = 7 - a.
Then we have:
a^2 + (7 - a)^2 = 25, or
a^2 + 49 - 14a + a^2 - 25 = 0, or
2a^2 - 14a + 24 = 0, or
a^2 - 7a + 12 = 0, which factors as follows:
(a - 3)(a - 4) = 0
This results in a = 3 and a = 4, in which case the equation a + b = 7 tells us that the b values are 4 and 3 respectively.
Solution set: (3, 4) and (4, 3)