222k views
5 votes
1.)A strong acid solution requires 3.2 grams of sulfuric acid (H2SO4). How many molecules of sulfuric acid are in the solution?

2.) While measuring out the sulfuric acid you accidentally spilled some of it! Before trying to clean it up you put some baking soda (NaHCO3) on to it neutralize it. If you scatter 7.8 g of baking soda on the acid how many moles of baking soda have you used?

User Marquise
by
3.4k points

1 Answer

3 votes

Answer: 1. There are
0.20* 10^(23) molecules of sulfuric acid in the solution.

2. 0.093 moles of baking soda have been used.

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
6.023* 10^(23) of particles.

To calculate the moles, we use the equation:

1.
\text{Number of moles of sulpfuric acid}=\frac{\text{Given mass}}{\text {Molar mass}}=(3.2g)/(98g/mol)=0.033moles

1 mole of
H_2SO_4 contains =
6.023* 10^(23) molecules of sulfuric acid

Thus mole of
H_2SO_4 contains =
(6.023* 10^(23))/(1)* 0.033=0.20* 10^(23) molecules of sulfuric acid

There are
0.20* 10^(23) molecules of sulfuric acid in the solution.

2.
\text{Number of moles of baking soda}=\frac{\text{Given mass}}{\text {Molar mass}}=(7.8g)/(84g/mol)=0.093moles

0.093 moles of baking soda have been used.

User Jason Beck
by
3.4k points