184k views
0 votes
9. Determine the equation of a line that passes though the points (3,-4) and (6,2). [​

1 Answer

4 votes

Answer:

y=2x-10

Explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (3,-4), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=3 and y1=-4.

Also, let's call the second point you gave, (6,2), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=6 and y2=2.

Now, just plug the numbers into the formula for m above, like this:

m=

2 - -4

6 - 3

or...

m=

6

3

or...

m=2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

User Pritam Banerjee
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories