Question

Help pure people pls

Answer 1

Option (B). Perimeter of the quadrilateral ABCD= 14.6 units

Explanation:

From the figure attached,

Coordinates of the vertices are A(3, 5), B(1, 3), C(3, -1), D(5, 3).

Length of AB =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}`

=
`√((3-1)^2+(5-3)^2)`

=
`√(8)`

= 2.83 units

Length of AD =
`√((3-5)^2+(5-3)^2)`

=
`√(8)`

= 2.83 units

Length of BC =
`√((1-3)^2+(3+1)^2)`

=
`√(20)`

= 4.47 units

Length of DC =
`√((5-3)^2+(3+1)^2)`

=
`√(20)`

= 4.47 units

Perimeter of the quadrilateral = AB + AD + DC + BC

= 2.83 + 2.83 + 4.47 + 4.47

= 14.6 units

Option (B) is the answer.