Question

A grocery store has a discount of 13% off hand soap. At the same time the hand soap manufacturer has a coupon for $2.00 off. Assuming both promotions can be applied at the same time how much more would you pay if you applied the coupon first?

Answer 1

$0.26

Step-by-step explanation: I took the test

Answer 2

`\$0.26` has to be paid more if the coupon is applied first

Explanation:

Given: A grocery store has a discount of 13% off hand soap. At the same time the hand soap manufacturer has a coupon for $2.00 off.

To find: how much more would be paid if the coupon is applied first

Solution:

Let $ x denotes cost of hand soap

Case 1:

If the discount is given first,

cost of hand soap =
`x-(13)/(100) x=\$ (87)/(100)x`

If the coupon for $2.00 off is applied,

Final cost of the hand soap =
`\$\,((87)/(100)x-2)`

Case 2:

If the coupon for $2.00 off is applied first,

cost of hand soap =
`\$(x-2)`

If the discount is given then,

final cost of the hand soap =
`(x-2)-(13)/(100)(x-2)=(87)/(100)(x-2)` =
`(87)/(100)x-(87)/(50)`

Here,

`(87)/(100)x-(87)/(50)-(87)/(100)x+2=(13)/(50)=\$0.26`

So,
`\$0.26` has to be paid more if the coupon is applied first.