Question

If cos 67 degrees is close to 2/5 which is closest to the length of no

PO=100cm
P=23 degrees

Answer 1

HI!!! I just finished the unit 7 lesson 11 unit test!! Here are the answers: :)

1. A: 2

2. C: 225

3. C: pi/4

4. A: -465

5. C: 0

6. B: 210

7. B: 2pi

8. A: 52

9. C: 40

10. C: 3rd graph

11. A: y=sin pi/265

12. B: 1/4pi

13. D: y=3cos2

14. A: sqrt3/3

15. C: 0

16. C: 3rd graph

17. A: 187

18. C: sqrt2/2

19. B: 1+sin theta

20. D: 45

21. D: 0.64

22. A:80

23. C: pi/2, 5pi/4, 3pi/2, 7pi/4

24. C: csc theta =13/12, sec theta= 13/5

hope this helps someone :)))

Answer 2

40 cm

Explanation:

In the right triangle PNO:

• ∠N = 90°

• PO = 100cm (the hypotenuse of the triangle)

• ∠P = 23°

• ∠O = 90° - 23° = 67°

• side NO is adjacent to ∠O

By definition:

cos(β) = adjacent/hypotenuse

Replacing with data and solving for NO:

cos(∠O) = NO/PO

2/5 = NO/100

NO = (2/5)*100

NO = 40