Question

Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point elevation constant of 2.53°C•kg/mol.

Answer 1

First Question:

C. ΔTb = Kbm

Second Question:

C. 9.36° C

Third Question:

89.5

Explanation:

Got it right.

Answer 2

Answer: The boiling point of a 3.70 m solution of phenol in benzene is
`89.5^0C`

Step-by-step explanation:

Elevation in boiling point:

`\Delta T_b=i* k_b* m`

where,

`\Delta T_b` = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

`k_b` = boiling point constant =
`2.53^0C/kgmol`

m = molality = 3.70

`T_(solution)-T_(solvent)=i* k_b* m`

`T_(solution)-80.1^0C=1* 2.53* 3.70`

`T_(solution)=89.5^0C`

Thus the boiling point of a 3.70 m solution of phenol in benzene is
`89.5^0C`