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What’s the vertex of y=1/3(x+2)^2-5

What’s the vertex of y=1/3(x+2)^2-5
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What’s the vertex of y=1/3(x+2)^2-5

User Bmauter
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2 votes

Answer:

vertex is (2,-5)

Explanation:

y = a(x – h)^2 + k

the vertex is (h,k) in the equation h =2 and k = -5

What’s the vertex of y=1/3(x+2)^2-5-example-1
What’s the vertex of y=1/3(x+2)^2-5-example-2
User Jpgc
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