Question

Find the perimeter and area of the rectangle given below. A rectangle ABCD with vertices ​A(2​,4​), ​B(2​,7​), ​C(5​,7​), and ​D(5​,4​).

Answer 1

The perimeter of the rectangle is 15 units and the area of the rectangle is 0 square units.

Step-by-step explanation:

To find the perimeter of a rectangle, we add the lengths of all four sides. In this case, we have side AB with a length of 3 units, side BC with a length of 5 units, and side CD with a length of 3 units. To find side AD, we subtract the y-coordinates of points B and C, which gives us a length of 4 units. Therefore, the perimeter of the rectangle is 3 + 5 + 3 + 4 = 15 units.

To find the area of a rectangle, we multiply the length by the width. The length of the rectangle is the difference between the x-coordinates of points B and A, which is 0 units. The width of the rectangle is the difference between the y-coordinates of points B and C, which is 3 units. Therefore, the area of the rectangle is 0 * 3 = 0 square units.

Answer 2

Answers:

Perimeter=6 units

Area=0 units ^2

please see the attached picture for full solution

hope it helps

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