83.1k views
3 votes
Help please!

How does the function f(x)=x^2−4x−21 illustrate the Fundamental Theorem of Algebra?

Fill in the blanks. (Hint: Your answers are numbers.)

The degree of f(x) is _____. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly _____ zeros. Those zeros are 7 and _____.

User Habiat
by
6.5k points

1 Answer

4 votes

f(x)=x²−4x−21

The degree is the biggest power of x. That's a polynomial of degree 2, also called a quadratic function. Let's find its zeros.

0 = x²−4x−21 = (x - 7)(x+3)

x=7 or x=-3

The fundamental theorem guarantees every non-constant polynomial with complex coefficients has a complex zero, let's call it r. If we divide the polynomial by x-r there won't be any remainder and we'll get a new polynomial, one degree less. The fundamental theorem again applies and (if it's not a constant polynomial) we are assured of another zero, s. We divide by x-s and get a new polynomial of degree one less. We repeat all this until we get a constant polynomial (degree zero). So we get a zero for every degree. They're not necessarily all different.

Answer:

The degree of f(x) is 2. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly 2 zeros. Those zeros are 7 and -3.

User Ihtkwot
by
8.2k points