Question

An open-pipe resonator has a length of 2.39 m. Calculate the frequency of its third harmonic if the speed of sound is 343 m/s.

80 Hz
115.7 Hz
215.27 Hz
100.1 Hz

Answer 1

f = 215.27 Hz

Step-by-step explanation:

We have,

An open-pipe resonator has a length of 2.39 m.

It is required to find the frequency of its third harmonic if the speed of sound is 343 m/s.

For third harmonic, its length is equal to,
`l=(3\lambda)/(2)`

So,

`(3v)/(2f)=2.39`

f is frequency in its third harmonics

`f=(3v)/(2* 2.39)\\\\f=(3* 343)/(2* 2.39)\\\\f=215.27\ Hz`

So, the frequency of its third harmonic is 215.27 Hz.