Question

Calculate the transfer of energy by a force of 15N when it moves the object by a distance of 5m

a. In the direction of the force

b. In a direction at 60° to the direction of the force


c. At right angles to the force

NEED EXPLAINATION

Answer 1

a) 75 J

b) 37.5 J

c) 0

Step-by-step explanation:

Work is the force exerted on an object causing it to move, Work is the product of force and displacement. Work is not done if the force and displacement are at right angles to each other. It is given by:

`Work(energy)=Fxcos(\theta)`

F is the force, x is the displacement and Θ is the angle between force and displacement.

a) Force (F) = 15N and distance (x) = 5. Since it is in the direction of the force, Θ = 0

`Work(energy)=Fxcos(\theta)= 15*5*cos(0)=75J`

b) Force (F) = 15N and distance (x) = 5. Θ = 60

`Work(energy)=Fxcos(\theta)= 15*5*cos(60)=37.5J`

c) Force (F) = 15N and distance (x) = 5. Θ = 90

`Work(energy)=Fxcos(\theta)= 15*5*cos(90)=0`