Question

A 50.0 mL sample of 6.0 M HCl was diluted to a final volume of 250.0 mL What was the new molarity?

Answer 1

1.2M

Step-by-step explanation:

Initial Volume 0.05L

Final Volume 0.250L

HCl Molar mass: 36.46 g/mol

M = 6M HCl

Molarity = mol solute / L of solution

Inital M = Molarity = 6

mol solute = X = unknown

L of Solution = 0.05L

6 = X / 0.05

X = 0.3

X = 0.3/0.25

X = 1.2 M

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