Question

94 POINTS!!!!!! EASY STATS QUESTION. SHOW WORK

A jar contains 4 marbles - 3 Red & 1 Blue. Two marbles are drawn with replacement after each draw. What is the probability that the same color marble is drawn twice?

Answer 1

Answer: hii :)

5/8

Explanation:

The probability of a red marble being drawn in both turns = 9/16, and the probability of a white marble being drawn in both turns = 1/16. So, the total probability = (9/16) + (1/16) = 10/16 = 5/8.

Hopefully this helps you

- Matthew

Answer 2

`\sf \frac58`

Explanation:

Given:

• 3 red marbles
• 1 blue marbles
• Total marbles = 4

`\sf Probability\:of\:an\:event\:occurring = (Number\:of\:ways\:it\:can\:occur)/(Total\:number\:of\:possible\:outcomes)`

`\implies \sf \textsf{P(red marble)}=(3)/(4)`

`\implies \sf \textsf{P(blue marble)}=(1)/(4)`

As the marbles are replaced:

`\implies \sf \textsf{P(red marble) and P(red marble)}=(3)/(4) * (3)/(4)=(9)/(16)`

`\implies \sf \textsf{P(blue marble) and P(blue marble)}=(1)/(4) * (1)/(4)=(1)/(16)`

Therefore:

`\implies \sf \textsf{P(red and red) or P(blue and blue)}=(9)/(16)+(1)/(16)=(10)/(16)=\frac58`