Question

8(y^0) + (-7)(y^0)=________

Answer 1

1

Explanation:

8(y^0) + (-7)(y^0)

Remove parentheses: (a)=a

= 8
`y^(0)`-7
`y^(0)`

Add similar elements: 8
`y^(0)`-7
`y^(0)`=
`y^(0)`

=
`y^(0)`

Apply rule
`a^(0)` = 1,
`\alpha \\eq 0`

= 1

Answer 2

Since anything to the power of 0 is 1.

You get

8(1)+(-7)(1)
8-7
1