Question

In the following triangle theta=60.Find the values of the angles of the angles B and B'

Answer 1

A. B = 64.13° or B' = 115.87°

Explanation:

The given angle is opposite the shortest of the given sides, so there are two possible solutions using the Law of Sines. Either way, we have ...

sin(B)/16 = sin(θ)/15.4

B = arcsin(16/15.4·sin(60°)) ≈ arcsin(0.899767)

B = 64.13° or B' = 180° -64.13° = 115.87°