Question

How many oxide ions are in 0.55 grams of titanium oxide?

Answer 1

Answer: There are
`0.052* 10^(23)` oxide ions

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(0.55gg)/(64g/mol)=0.0086moles`

1 mole of TiO contains =
`6.023* 10^(23)` oxide ions

Thus 0.0086 moles of TiO contains =
`(6.023* 10^(23))/(1)* 0.0086=0.052* 10^(23)` oxide ions

There are
`0.052* 10^(23)` oxide ions