Question

Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water

and another formed by adding 10.0 grams of sucrose (C12H22O11) to 1.0 L of water. Which of the
two solutes produces the lower reduction in the vapor pressure of the solvent? Explain fully.

Answer 1

Step-by-step explanation:

Lowering of vapour pressure of solvent is proportional to number of moles of solute dissolved in it per litre .

No of moles of glucose dissolved

= mass dissolved / molecular weight of glucose

= 10 / 180

= .055 moles.

No of moles of sucrose dissolved = 10 / 342

= .029 moles.

So reduction in vapour pressure will be lower of solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.