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22 votes
22 votes
From her eye, which stands 1.66 meters above the ground, Deondra measures the

angle of elevation to the top of a prominent skyscraper to be 70°. If she is standing at
a horizontal distance of 276 meters from the base of the skyscraper, what is the
height of the skyscraper? Round your answer to the nearest tenth of a meter if
necessary.

User Dheeraj Reddy
by
3.0k points

1 Answer

23 votes
23 votes

Answer:

760 m

Explanation:

You can draw a right triangle.

For the angle of 70°, 276 m is the adjacent side.

The heigh of the building above 1.66 m is the opposite side.

tan x = opp/adj

tan 70° = h/276

h = tan 70° × 276

h = 758.3

h is the height above 1.66 m.

height = 758.3 m + 1.66 m = 759.96 m

Answer: 760 m

User Scotty Bollinger
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3.0k points