Question

Someone tell me how to balance the equation by hit and trial method...​

Answer 1

1. 3H2S + 2HNO3 -----> 2NO + 4H2O + 3S

Step-by-step explanation:

H2S + HNO3 -----> NO + H2O + S

There are 3 O's on left and only 2 on right so put 2 before NO:

H2S + HNO3 ----> 2NO + H2O + S

Now we have 2 N's on left so put 2 before HNO3:

H2S + 2HNO3 -----> 2NO + H2O + S

4 H's on the left so

H2S + 2HNO3 -----> 2NO + 2H2O + S

That makes 6 O's on left so we write

H2S + 2HNO3 ----> 2NO + 4H2O + S

Now there 8 H's on the right but only 4 on the right so we adjust H2S and S:

3H2S + 2HNO3 -----> 2NO + 4H2O + 3S

Now it balances!

Basically you 'play around' with the quantities of each element in this way.