Question

How much will stretch a spring that has spring constant of 735 N/m, if you vertically hung a 2. 30 kg object from it. How much work must an external agent do to stretch the same spring 6. 50 cm from its unstretched position?

Answer 1

F = - K X

X = -F / K = M g / K = 9.8 * 2.3 / 735 = .03 m = 3 cm

W = 1/2 K X^2

W = 1/2 * 735 N/m * .065^2 m^2 = 1.55 Joules

Answer 2

Part 1 = 0.03m, Part 2 = 1.4651J