Question

Can someone help me I was doing good and then I got stuck on this question what I can’t figure out is how you get the voltage when you only have the watt and resistance .

A 60.0 Watt lightbulb has an operating resistance of 220 Ω.

Calculate the operating voltage of this lightbulb.

Answer 1

114.89 V

Explanation:

Watts are a measure of power, and there is an equation that relates power, voltage, and resistance. It goes like this:

P=(V^2)/R

Now to find the voltage you want to solve for V

PR = V^2

V =
`√(PR)`

Now substitute your numbers into the equation and you get your answer

V =
`√((60)(220))`

V =
`√(13200)`

V = 114.89 V