Question

The solubility of a solute and solvent at a given temperature is 30.65 g/100 mL.

How much of the solute could be dissolved in 2 L of the solvent?

Please remember to consider significant figure or precise value rules.

Answer 1

613.0 g

Step-by-step explanation:

2 L = 2000 mL

(30.65 g/100 mL)*2000 mL = 613.0 g

Answer 2

Given:

• Solute + solvent = 30.65 g/100 mL

• Solvent = 2L

Solution:

Firstly,

We converted L to mL

2 L = 2 × 1000 mL = 2000 mL [ 1 L = 1000 mL ]

Now,

Solute = 30.65/100 × 2000

= 30.65 × 2000 / 100

= 61,300/100

= 613