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3 votes
What is the following product?

RootIndex 3 StartRoot 4 EndRoot times StartRoot 3 EndRoot
2 (RootIndex 6 StartRoot 9 EndRoot)
RootIndex 6 StartRoot 12 EndRoot
RootIndex 6 StartRoot 432 EndRoot
2 (RootIndex 6 StartRoot 3,888 EndRoot)

User Mkrinblk
by
4.6k points

2 Answers

5 votes

Answer:

C edge 2021 :)

Explanation:

User Hoby
by
4.1k points
4 votes

Answer:

RootIndex 6 StartRoot 432 EndRoot

Explanation:

To find the following product


\sqrt[3]{4} * √(3)

we can rewrite the radicals and then replace them into the multiplication, as follows:


\sqrt[3]{4} = 4^{(1)/(3)} = 4^{(1)/(3) * (2)/(2)} = 4^{(2)/(6) = \sqrt[6]{16}


√(3) = 3^{(1)/(2)} = 3^{(1)/(2) * (3)/(3)}} = 3^{(3)/(6)} = \sqrt[6]{27}


\sqrt[3]{4} * √(3) = \sqrt[6]{16} * \sqrt[6]{27} = \sqrt[6]{16 * 27} = \sqrt[6]{432}

User Daniel De Paula
by
4.5k points