Answer:
3808
Explanation:
Given the sequence: 13,19,25
First Term, a=13
Common Difference, d=19-13=25-19=6
Since we have a common difference, the sequence is an arithmetic sequence.
We determine the sum of any nth term of an arithmetic sequence using the formula:
![S_n=(n)/(2)[2a+(n-1)d] \\n=34, a=13, d=6\\$Therefore:\\S_(34)=(34)/(2)[2(13)+(34-1)*6]\\=17[26+33*6]\\=17[26+198]\\=17*224\\S_(34)=3808](https://img.qammunity.org/2021/formulas/mathematics/high-school/1y8h5xdkghjs1odtaravxfz8y6f514w66a.png)
The sum of the first 34 terms is 3808.