Question

Which is the anode (oxidation) and cathode (reduction)?

2H+ + 2e- --> H2(g)

2Cl- --> Cl2(g) + 2e-

Answer 1

2H+ + 2e - ---> H2(g) is the cathode

2Cl - ---> Cl2(g) + 2e - is the anode

Step-by-step explanation:

Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.