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Solve the following equation. Then place the correct number in the box provided. 3y + 2 ≥ 5y +8

User Prabodh M
by
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2 Answers

4 votes

Answer:


y\leq -3

Explanation:


3y+2 \geq 5y+8 \\\\3y\geq 5y+6\\\\-2y\geq 6\\\\y\leq -3

Hope this helps!

User Thaer A
by
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5 votes

Answer:

-3 ≥y

Explanation:

3y + 2 ≥ 5y +8

Subtract 3y from each side

3y-3y + 2 ≥ 5y-3y +8

2 ≥ 2y +8

Subtract 8 from each side

2-8 ≥ 2y +8-8

-6 ≥ 2y

Divide by 2 on each side

-6/2 ≥ 2y/2

-3 ≥y

User Simme
by
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