Question

A car starting from rest, travels 0.40 km in 11.0 s. What is the

magnitude of its constant acceleration?​

Answer 1

6.61 m/s²

Step-by-step explanation:

Given:

Δx = 0.40 km = 400 m

v₀ = 0 m/s

t = 11.0 s

Find: a

Δx = v₀ t + ½ at²

400 m = (0 m/s) (11.0 s) + ½ a (11.0 s)²

a = 6.61 m/s²