Question

The final velocity, V, of an object under constant acceleration can be found using the formula v2=v2+2as, where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

Answer 1

Answer: a = (V^2 - v^2)/2s

Explanation:

The equation for the final velocity is:

V^2 = v^2 + 2*a*s

where V is the final velocity, v is the initial velocity, a is the acceleration and s is the distance.

Now, we want to solve this formula for a, this would mean isolate a in one side of the equation, this is pretty simple, first we pass subtract v^2 in both sides.

V^2 - v^2 = v^2 + 2*a*s - v^2

V^2 - v^2 = 2*a*s

now we can divide by 2*s in both sides:

(V^2 - v^2)/2s = 2*a*s/2s = a

a = (V^2 - v^2)/2s