Question

Was the object accelerating during the time interval labeled “B”?
A) Yes
B) No

Answer 1

There's not enough information in the graph to determine whether it was or it wasn't. It could have been, but we can't tell.

Before I explain this answer, it's VERY important to know exactly what "accelerating" means:

-- "Accelerating" does NOT always mean "speeding up".

-- "Accelerating" means ANY change in velocity.

-- That can be ==> speeding up, or ==> slowing down, or ==> turning.

This graph is labeled "Velocity vs Time", but it isn't really. "Velocity" means speed AND direction. The graph only shows us the object's speed, but nothing about its direction.

During time-interval-B, the speed isn't changing, but the object could still be changing direction, like turning a corner, or on a curved path. We don't know. The graph doesn't show us that information.

The object could be accelerating during time-interval-B. It's true that the speed wasn't changing. But maybe the direction was. If the direction was changing, then we have to say the object was 'accelerating' during the interval labeled B .

Answer 2

B) No, Interval B has constant velocity, and the velocity remains at 20 units throughout the interval.

Two intervals, A and B, with corresponding points on a graph where the x-axis represents time, and the y-axis represents velocity. Let's analyze the information for each interval.

Interval A:

Points: (0,0), (1,4), (2,8), (3,12), (4,16), (5,20)

From these points, you can observe that the velocity is increasing linearly with time in Interval A. The relationship between time (t) and velocity (v) seems to be given by the equation
`\(v = 4t\).`

Interval B:

Points: (6,20), (7,20), (8,20), (9,20), (10,20)

In Interval B, the velocity remains constant at 20 units throughout the entire interval. This means that there is no change in velocity with respect to time in Interval B.

Interval A exhibits linearly increasing velocity with time, given by
`\(v = 4t\).`

Interval B has constant velocity, and the velocity remains at 20 units throughout the interval.

Therefor correct answer: B) No, Interval B has constant velocity, and the velocity remains at 20 units throughout the interval.