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2 votes
I wrote a rock paper scissors game in python but I cannot get it to play again once the user choices a yes option. The rest of the program works.

Here's what I have:
import random
playAgain = True
choice = input("Enter Rock(R), Paper(P), or Scissors(S): ")
computer = random.randint(1, 3)
if computer == 1:
print("Computer played R.")
elif computer == 2:
print("Computer played P.")
else:
print("Computer played S.")
#Winning conditions
if computer == 1 and choice == "R":
print("Computer played Rock.")
print("Tie")
elif computer == 2 and choice == "P":
print("Computer played Paper.")
print("Tie")
elif computer == 3 and choice == "S":
print("Computer played Scissors.")
print("Tie")
elif computer == 1 and choice == "S":
print("Computer played Rock.")
print("You Lose")
elif computer == 2 and choice == "R":
print("Computer played Paper.")
print("You Lose")
elif computer == 3 and choice == "P":
print("Computer played Scissors.")
print("You Lose")
elif computer == 1 and choice == "P":
print("Computer played Rock.")
print("You Win")
elif computer == 2 and choice == "S":
print("Computer played Paper.")
print("You Win")
elif computer == 3 and choice == "R":
print("Computer played Scissor.")
print("You Win")
#Play again?
choice = input("Play Again? ")
while playAgain == True:
if choice == "y":
playAgain = True
elif choice == "yes":
playAgain = True
if choice == "Yes":
playAgain = True
elif choice == "Y":
playAgain = True
elif choice == "n":
print("Thanks for playing!")
exit()
elif choice == "no":
print("Thanks for playing!")
exit()
elif choice == "N":
print("Thanks for playing!")
exit()
elif choice == "No":
print("Thanks for playing!")
exit()
else:
print("Please input a vaild option.")
choice = input("Play Again? ")

1 Answer

3 votes

Answer:

Make it an IF then thing where it says IF playAgain = True { your program

}else if(playAgain = False){ then go back to home screen

}

Step-by-step explanation:

User Jack Brown
by
4.8k points